Any good ways to quickly look up the Season 3 and Season 4 ranks of everyone in a match?

CupcakeTrap·11/9/2014, 8:39:16 AM·1 votes·42,746 views

LoL Nexus used to do this. Recently, they removed the S3 rank information. OP.GG does this, but it takes a long time to punch in everyone's name.

I'm asking because scoring Factions matches requires knowing the Season 3 and Season 4 rank of all the Summoners in the match. We use the higher of the two, because sometimes you have someone who was, say, Diamond in S3, but has stopped playing Ranked in S4. For fairness reasons, you probably shouldn't be counting them as unranked or whatever. However, without a convenient LoL Nexus screenshot showing both S3 and S4 rank, it's quite tedious to score matches.

I imagine the Riot API provides functions for looking up someone's rank from a particular season, but I'm not aware of any sites that will automatically do this for everyone in a given match.

Any ideas?

10 Comments

RiotSargonas11/13/2014, 6:33:09 PM3 votes

Unfortunately, our API's do not provide season stats for seasons prior to the previous one. In other words, once S4 closed out, everyone's "previous season" data point was updated to the S4 rank. This is likely why those sites no longer have it as well, since they were populating that field off of the same endpoint.

The new Match History we have now archives a lot more data in a lot more ways, and has a lot of new APIs around it. While the data only goes back to around May, when it was first brought online internally, hopefully it will allow for some better long term data tracking around these things in the future.

ParinoidPanda11/9/2014, 10:28:36 AM2 votes

Lolking. Has season 1 If they played.

RoyaiChaos11/9/2014, 6:18:05 PM1 votes

Can't find any :C I swear that they used to have ranked borders in lolskill but they three high elo matches I checked didn't have them. Kassed.in is a no as well. Otherwise the only solution I could think of would be to spectate and screenshot which honestly isn't any more convenient.