buying champions

Zanader··1 votes·577 views

how many games do you have to actully play to get every single champion in the game currently?

11 Comments

Dabrick011 votes

Depends, you don't get a finite amount for each game.

However, my calculations have returned some shocking results.

Too fucking much IP.

Penns1 votes

How can you not get a finite amount of ip? oo

Dabrick011 votes

Ok, your question was how many games do you have to play. I can't tell you that as it depends on a lot of factors there IS a finite amount of IP for all the champs in the game, but how many games it takes to get that is a different story.

Primaquarius1 votes

At least 3 years, give or take, if you don't use RP

Zanader1 votes

i wish champions where wayyyyyy cheaper cause its so tiresome to actully try and get every single one i wanna do it cause i wanna be flexable in game but ugh.. like i don't wanna play over 1000 and over 1000 games... sigh and paying real money you know... isent a fun idea

Zanader1 votes

rito plz

LostFr0st1 votes

There's 133 champs (pretty sure?) You'd need 1700 x 3 x 133 = 678 300 ip to get them using rerolls of the 1700ip champ shards in hextech crafting. If you buy the 450, 1300, 3150, and 4800 champs for ip straight up and then use 1700ip champ shards for a guaranteed re-roll into a 6300 then the total ip needed becomes 479400. You'd have to divide that by your average ip per game, which depends on the mode, and somehow account for WotD to get your answer.

Hyperiön1 votes

Figure on average 80 IP, thats only 5640 games.

Weathered1 votes

I've been playing for over a total 1.8k hours logged and I still don't have all the champions. A lot of games.

PureSilvrr1 votes

I know.. I still don't have all the champs... and I still need to start buying runes.... and that's going to be hell

His Goatliness1 votes

My main account has somewhere around 5k normals I think, and I don't have them all. Granted I probably got a lot of runes but I'm missing 7 currently. (I also have I think at least 500<games of aram.

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