if ekko is balanced then 0=1

S1=1-1+1-1+1-1+1...... S1=1+(-1+1)+(-1+1)......=1 S1=(1-1)+(1-1)+(1-1).....=0 2S1=1 -> S1=1/2

S2=1-2+3-4+5-6+7.....

2S2=1-2+3 -4+5-6+7..... --------------1 -2+3 -4+5-6..... --------=1-1+1 -1+1 -1+1.....=1/2

S2= 1/(2*2)=1/4

S3=1+2+3+4+5+6+7........

S3-S2=1+2+3+4+5+6+7.......... ---------+(-1+2 -3+4 - 5+6 -7......... -----------=0+4+0+8+0+12+0........... -----------=4(1+2+3..........) S3-S2=4S3 -3S3=S2 S3=S2/-3=1/(4*-3)=-1/12

2S3-2S3=1+2+3+4+5+6+7......... ---------------------- -1 -2 -3 -4 -5 -6........ ---------------------- -1 -2 -3 -4 -5 -6........ --------------------------- 1+2+3+4+5........ ----------------=1+0+0+0+0+0+0........=1

2*-1/12-2(-1/12)=1 0=1

Answer: Ekko is balanced. #trustmath