Kindred One For All would be so scary
farming top
five marks appear on him at once
farming top
five marks appear on him at once
"Okay guys, let's ult in 3... 2... 1...
Stops farming and looks up "This is not k"
But then he oranges and is K.
I'm a Gangplank main, and part of that is knowing when your oranges will not make you k. This is one of those times
Former Gangplank main. Uhhhhhhhh.... Okay. I have to agree.
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Be the orange.
The truest pirate is one with the citrus

http://i.ytimg.com/vi/IfXyEmG6loo/maxresdefault.jpg Well that was pointless
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atleast they have no damage, but its not like you have any either now XD
Yeah, they'd literally be able to fuel each other's heals and just poke you to death.
they would run oom fast lol
I've played karthus vs karthus one for all. It was actuallly pretty fun. There was a bit in the mid game where both sides would ace each other, but smart players built zhonyas/banshees pretty early so then it became more about landing the the q. It felt great if you were the last one and your team alive and you coudl just ult for a triple kill after a teamfight (since the enemy zhonyas and veils would all be popped by then).
Five Kindred would be rather amusing.
Alpha Wolf: That was OUR kill!
**Beta Wolf: **No, ours!
Gamma Wolf: Mine!
Delta Wolf: IT WAS OURS!
Epsilon Wolf: SQUIRREL!
Wolf Pack: WHERE?
+1 for the UP reference
Speaking of
, imagine a OFA match with five of him.
You get ulted forward, then back, then forward, take it back now ya'll, one whallop. Five whallops. And so on like the song.
I would have loved to see a One-for-All Morde team after his first round of rework.
: Meet all our pets...
problem is there would be no one left to meet them.
Well, If you walked into lane with five dragons they'd at least get a peak before they got shreaded by everything Morde had to offer.
hmm with Riots spaghetty code it's really impossible to say whether they would get all five or only one pet per takedown.
I thought the latter, so for five pets you'd need to kill five enemys. But i guess if one of the enemies is dragon then there could be one lonely terrified tank left to face the spectacle.
Well I can't say for sure because I don't know their code either, but I assumed that all 5 Mordes would get a dragon as long as they all at least got one hit on the dragon. Riot can you come settle this please?
and a 5v5 becomes a 4v6 - 3v7 - 2v8 - 1v 9 o.O then 10 characters running down the base >.<
like dog owners at a dog show :p
hey guys, like my
?
he's nice, but my
has a nicer coat :p
please, the quality of my
's void blade is second to none.
Look at my new Dragon everybody :D
...
Except the entire jungle is shroomed up.
unfortunately all I got to play was 5blitzcrank 5lux come on guys lets get more creative!
ok but what about like 5x
? like can u imagine how broken that could get if the enemy didn't counterpick?
also all4one ekko would be an aoe wombo nightmare
i just cried laughing imagining 5 kalistas ulting eachother
Like dolls we play with in mother country.
did somebody say china doll
?
Russian Doll,but close enough i mean they are right next to each other on a map. RIGHT?! RIGHT!KRDOEWFKGRWF?!
I really thought you were talking about 
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I really thought you were talking about
Oh lord. When you become the villain and all 5 Garen's just stare at you, licking each other's lips, waiting for their ults to come.
Spoooooooky
now he can not see you
one for all.
No one dies, literally no one will die.
The question is if the mark is specific to who laid it, or if one mark works for everyone.
If the latter, just mark one person on the enemy team each, and every kill and assist you get steadily ramps up your team's damage...
In this situation would staying in fountain actually be the right thing to do?
5 anivia's
You shall not pass!
Minions have to walk out of lane to get around the wall of china. Lol
Imagine all for one Tahm Kench XD
The only problem here is that the have to go through a sea mushrooms compliments of the other 4 Teemos.
But it's a one for all.
Both sides aren't playing the same champion in One for all.