Getting teamed with someone i reported

Darkw1ng··1 votes·240 views

So why in the hell do i queue into a game and get placed on the same team as someone who i reported the game before. Honestly Riot if i wanted to play with this kid and his 4/15/5 guardian dariusing ass i would party up with the guy, but no throw two games of enjoyment out the window.... Thanks devs for making a fantastic and fun game experience for all of the playersitem 3070

5 Comments

archerno12 votes

So you placed false report on him and you expect it to mean something? You do realize that false reports do nothing? Placing false report is like yelling at the wall because its raining.

Darkw1ng1 votes

no i placed a report cause he was toxic as fuck and then when he saw me and my duo the next game he told us he was going to int

Potchikir1 votes

if u wont get matched with people u reported then everyone would report faker and he will be unable to play on his main account because there is no one to play with him

Darkw1ng1 votes

I don't care if i'm against him, just don't want him on my team, as i said nothing about getting matched with him. just getting teamed with him...[slayer-jinx-catface] Reading comprehension is important

AeroWaffle1 votes

If you both queued up at the same time it's not that unusual. Both of you would have roughly the same MMR.

Implementing an avoid style system is, well, "avoid"ed because of the potential abuse many players will use it for. Many players want to win (strange I know), so they'll use any method they think will increase their chances of winning. With an avoid system (be it included in the report system or separate), many people will use it to just not be queued with people who they believe to be lowering their chances of winning and not just those with poor behavior. This will result in players that play poorly having a harder time finding a match and that's not fair to them. The punishment for playing poorly should only be losing the game more often. They don't need longer queue times stacked on top of that.

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