Riot what is this?

zZLucasGaming·8/14/2017, 9:40:46 PM·1 votes·321 views

My friends, all of them, play rarly league and don't get so many honours, but I get 2-3 honours at 2 matches so like 20 honours a day. My freinds play like 10 matches a week and I play 25 matches a week! They get 2-3 honours at 2 matches, I get 2-3 honours at 2 matches. The thing is that, if you didn't see, they play less then me so that means they have less honours. Then why do they all have lvl 3 and I don't? If they have less honours than me?? Riot, WHERE IS YOUR LOGIC??[zombie-brand-facepalm]

2 Comments

Telephone Booth8/16/2017, 3:16:36 AM1 votes

They always get 3 and you always get 2. Their ratio of matches to honors is higher. Yeah you have more total, but they have a higher average of honors per game. If that's not true, show me the proof.

Master Noct8/17/2017, 5:11:44 AM1 votes

The honor system doesn't fully depend on how much honor you get (but which is nice to consider in this system), but how much AVERAGE honor you get.

So that means if you get 20-30 honor spread out through multiple games, at least 1-3 honors, your average is mid-high, since you're getting a lot of honors in a larger window of time. But if your friends are nailing much more honor in a shorter time, maybe 2-4, more consistently, their average will be much higher, and thus will need less progress to reach the next level.

This is funnily the same exact scenario as me and my girl (Mistress Nyx), where I got level 3 honor a lot faster than she did even though we pretty much constantly duo q'd and stopped playing altogether if one of us left. I ended up sometimes getting all honors on the team (4 of them), but ended up averaging on 2-3 per game consistently, but then she sometimes nailed all 4 every 3-4 games, and no less. While she might be getting more honor than I have constantly, she's taken a little longer to progress since it isn't as frequent.

Of course, this isn't a fail-proof way to see the system, since it can change, and might be wrong, but it's close.