I’m waiting on my flight at the airport, and I love math.
Ask me any (math) problem! Not the millenium problems, though, if I had the solutions to those I wouldn’t be waiting at an airport.
Ask me any (math) problem! Not the millenium problems, though, if I had the solutions to those I wouldn’t be waiting at an airport.
Is mayonnaise an instrument?
how do i get a gf
[{quoted}](name=Count Calculus,realm=NA,application-id=yrc23zHg,discussion-id=8nfTLEQi,comment-id=,timestamp=2019-01-01T21:22:26.676+0000)
Ask me any (math) problem! Not the millenium problems, though, if I had the solutions to those I wouldn’t be waiting at an airport.
Edit: this is not the person I meant to quote xD
If you still want some: here is mine:
You have 9 pennies Each are visually identical One is a fake The fake one is either lighter or heavier
You have a Balance scale to check them
Can you identify the fake one with only 3 uses of the balance?
Not really a question but a math video I found really interesting:
Thought I'd share it.
i dunno if youre still answering but like math problem an airplane travels west at 180 km/h and returns east with the jet stream at 300 km/h. what was the average speed in km/h for the whole trip? math homework over break woO
If 3x−y=12, what is the value of 8x2y?
A) 212 B) 44 C) 82 D) The value cannot be determined from the information given.
A bit of an odd ball problem to throw at you, but I figure you might enjoy it.
As you probably know, going from a cube with sides of X to a cube with sides of 2*X, the mass doesn't increase 2 times, but rather 8 times. Similarly, going to sides of 0.5*X makes the mass 1/8th.
Lets say you had 2 cubes, one with sides of length X, the other length Y. If you decrease the side of the first cube by N and added that mass to the other cube, what formula would describe how much longer the other cube's sides are now (M)? Can this formula be adapted to two rectangular prisms, assuming the prisms are proportional in their dimensions?
Quote my comment @anyone. I want to get notifications when this thread gets a comment be it a Question or Answer. I also like this poster a lot.
Posting a potential answer to my own question.
The prism dimensions don't change the principle of doubling/halfing. A 7*3*1 prism has a volume of 21 units, which cubed gets a volume of 168 units. 168 = 7X*3X*1X 168 = (7*3*1)*X^3 168 = 21*X^3 8 = X^3 2 = X, Same as with the ordinary cube. (You can check, 168 = 14*6*2, which is what I originally did.)
Now, knowing that, I can apply the principles to two figurines - both originally 7*3*1
One becomes 4.5*1.5*0.5, or a volume of 3.375. This means it lost 21 - 3.375 = 17.625, which goes over to the other figurine, for a total of 21 + 17.625 = 38.625.
38.625 = 21*X^3 1.8392857142857142 = X^3 1.2252265501940295 = X
So the second figurine can be 1.225*7 units tall, or 8.575 units tall.
You might have seen this one, but it is one of my favorites :D Suppose you have a sphere of any volume but 0, and create 4 randomly placed points on the surface of the sphere. If you draw lines from the points to the inside of the sphere creating a tetrahedron, what are the exact chances that the tetrahedron made would encapsulate the center of the sphere? From the Putnam, took me about 3 weeks to solve for myself, but I'm not some savant lol. If you can get a piece of paper, drawing this out really helps. Good luck!
what's nine plus ten?